Two moles of helium gas undergoes a cyclic process as shown. Assuming the gas to be ideal find the difference in heat absorbed and heat rejected by the gas. (log 2 = 0.693)
Text Solution
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(0021)
F (2 – x) = f (2 + x) & f (20 – x) = f(x)
so, f(x) (i) symmetric w.r.t x = 2
(ii) periodic with period 16
f (0) = 5 & f (4) = 5
In every cycle at least two times f(x) = 5
so, f (0) = f (16) = f (32) = f (48) … = f (160) = 5
& f (4) = f (20) = f (36) …… = f (164) = 5
so at least for 21 values of x, f(x) = 5
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